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5 September, 21:57

A sample of phosphonitrilic bromide, PNBr2, contains 2.01 mol of the compound. Determine the amount (in mol) of each element present and the number of atoms of each element present in the sample.

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  1. 5 September, 22:30
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    2.01 moles of P → 1.21*10²⁴ atoms

    2.01 moles of N → 1.21*10²⁴ atoms

    4.02 moles of Br → 2.42*10²⁴ atoms

    Explanation:

    We begin from this relation:

    1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br

    Then 2.01 moles of PNBr₂ will have:

    2.01 moles of P

    2.01 moles of N

    4.02 moles of Br

    To determine the number of atoms, we use the relation:

    1 mol has NA (6.02*10²³) atoms

    Then: 2.01 moles of P will have (2.01. NA) = 1.21*10²⁴ atoms

    2.01 moles of N (2.01. NA) = 1.21*10²⁴ atoms

    4.02 moles of Br (4.02. NA) = 2.42*10²⁴ atoms
  2. 6 September, 00:12
    0
    For 2.01 moles PNBr2 we have 1.21 * 10^24 molecules

    P = 1.21 * 10^24 atoms

    N = 1.21 * 10^24 atoms

    Br = 2.42*10^24 atoms

    Explanation:

    Step 1: Data given

    Number of moles of PNBr2 = 2.01 moles

    Step 2: Calculate moles per element

    For 1 mol PNBr2 we have 1 mol P, 1 mol N and 2 moles Br

    For 2.01 moles PNBr2 we have:

    P = 2.01 moles

    N = 2.01 moles

    Br = 2 * 2.01 = 4.02 moles

    Step 3: Calculate atoms of each element

    For 2.01 moles PNBr2 we have 6.022 * 10^23 * 2.01 = 1.21 * 10^24 molecules

    P = 2.01 moles = 6.022 * 10^23 * 2.01 = 1.21 * 10^24 atoms

    N = 2.01 moles = 6.022 * 10^23 * 2.01 = 1.21 * 10^24 atoms

    Br = 4.02 moles = 6.022 * 10^23 * 4.02 = 2.42*10^24 atoms
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