If the dimensions of a cube-shaped cell with a volume of 1 pm were to

double, what would be the new surface area of the cell?

O A: 12 um

O B. 24 uma

O c. 6um

O D. 3 um

B

Explanation:

Assuming the units are all supposed to be the same

A cube shaped cell with a 1 um³ volume would have a dimensions of 1 x 1 x 1 (because volume = length x width x height and 1 x 1 x 1 = 1)

If we double the dimensions, we have a cube with the dimensions 2 x 2 x 2.

The surface area of each face of the cube is the length x width, so 2 x 2. This means the surface area of each face of the cube is 4 um².

There are 6 faces of a cube, so the total surface area is 6 x 4 um² = 24 um².