If 0.771 g of O3 reacts with 0.663 g of NO, how many grams of NO2 will be produced?

Mass = 0.92 g

Explanation:

Given dа ta:

Mass of O₃ = 0.771 G

Mass of NO₂ = 0.663 g

Mass of NO₂ produced = ?

Solution:

Chemical equation:

O₃ + NO → NO₂ + O₂

Number of moles of O₃:

Number of moles = mass / molar mass

Number of moles = 0.771 g / 48 g/mol

Number of moles = 0.02 mol

Number of moles of NO:

Number of moles = mass / molar mass

Number of moles = 0.663 g / 30 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of NO₂ with NO and O₃.

NO : NO₂

1 : 1

0.02 : 0.02

O₃; NO₂

1 : 1

0.02 : 0.02

Mass of NO₂:

Mass = number of moles * molar mass

Mass = 0.02 mol * 46 g/mol

Mass = 0.92 g