If you are given an ideal gas with pressure (P) = 259,392.00 Pa and temperature (T) = 2.00 oC

of 1 mole Argon gas in a volume of 8.8 dm3

, calculate R to the correct number of significant

figures and units under given condition.

R = 0.083 atm. L / mol. K

Explanation:

Given dа ta:

Pressure of gas = 259,392.00 Pa

Temperature = 2.0 °C

Moles = 1 mol

Volume = 8.8 dm³

R = ?

Solution:

First of all we will convert the units.

Pa to atm

259,392.00 / 101325 = 2.56 atm

dm³ to L

8.8 dm³ = 8.8 L

2.0 °C to K

2+273 = 275 K

Now we will calculate the R:

PV = nRT

R = PV / nT

R = 2.56 atm. 8.8 L / 1 mol. 275 K

R = 22.528 atm. L / 1 mol. 275 K

R = 0.083 atm. L / mol. K