How many joules of heat energy are released when 50.0g of water are cooled from 70.0C to 60.0C

2090 Joules

Explanation:

Heat energy is calculated by multiplying the mass of a substance by its specific heat capacity and by change in temperature.

That is;

Quantity of heat = Mass * specific heat capacity * change in temperature

Q = m*c * ΔT

In this case; we need to calculate the heat energy released by water

Mass of water = 50.0 g

Specific heat capacity of water = 4.18 J/g°C

Change in temperature = 10 °C (70°C - 60°C)

therefore;

Heat released = 50 g * 4.18 J/g°C * 10 °C

= 2090 Joules

Thus, the heat energy released when 50 g of water is cooled from 70°C to 60°C is 2090 Joules