If 1.12 g of phosphorus acid were dissolved in 100.0 mL of H2O. What is the concentration of the solution in molarity?

Answer: M=0.14

Explanation:The formula for concentration (molarity) is the moles of solute divided by the liters of solution. In order to find the moles of the solute, phosphorus acid, you need to convert 1.12 g to moles. The molar mass of phosphorus acid is 82 g/mol. 1.12g*1 mole / 82 g = 0.014 moles. Then convert mL to L. 100.0 / 1000 is 0.1. So the moles if 0.014 mol and the liters is 0.1 L. So, divide 0.014 by 0.1 and you get 0.14. So the concentration of the solution in molarity is 0.14