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26 December, 10:32

W (g) + X (g) - -> Y (g) + Z (g)

Gases W and X react in a closed, rigid vessel to form gases Yand Z according to the equation above. The initial pressure of W (g) is 1.20 atm and that of X (g) is 1.60 atm. No Y (g) or Z (g) isinitially present. The experiment is carried out at constanttemperature. What is the partial pressure of Z (g) when the partialpressure of W (g) has decreased to 1.0 atm?

A) 0.20 atm

B) 0.40 atm

C) 1.0 atm

D) 1.2 atm

E) 1.4 atm

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Answers (1)
  1. 26 December, 14:02
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    A) 0.20 atm

    Explanation:

    Let's consider the following reaction.

    W (g) + X (g) ⇄ Y (g) + Z (g)

    We can find the partial pressure of Z at a time that we will call the equilibrium using an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and complete each row with the pressure or change in pressure.

    W (g) + X (g) ⇄ Y (g) + Z (g)

    I 1.20 1.60 0 0

    C - x - x + x + x

    E 1.20 - x 1.60 - x x x

    At equilibrium, the partial pressure of W is 1.0 atm.

    1.20 atm - x = 1.0 atm

    x = 0.20 atm

    The pressure of Z is x = 0.20 atm
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