In an analysis of interhalogen reactivity, 0.440 mol of ICl was placed in a 5.00-L flask, where it decomposed at a high T: 2 ICl (g) ⇌ I2 (g) + Cl2 (g) Calculate the equilibrium concentrations of I2, Cl2, and ICl (Kc = 0.110 at this temperature). [I2]eq: M [Cl2]eq: M [ICl]eq: M

[I2] = [Cl2] = 0.0176 M

[ICl] = 0.0528 M

Explanation:

Step 1: Data given

Number of moles ICI = 0.440 moles

Volume = 5.00 L

Kc = 0.110

Step 2: The balanced equation

2 ICl (g) ⇌ I2 (g) + Cl2 (g)

Step 3: The initial concentrations

[[ICl] = 0.440 moles/5.00 L = 0.088 M

[I2[ = 0M

[Cl2] = 0M

Step 4: The concentrations at the equilibrium

[[ICl] = (0.088 - 2x) M

[I2[ = xM

[Cl2] = xM

Step 5: Define Kc

Kc = 0.110 = [I2][Cl2] / [ICl]²

0.110 = x² / (0.088 - 2x) ²

0.332 = x (0.088 - 2x)

x = 0.332 * (0.088 - 2x)

x = 0.029216 - 0.664x

1.664x = 0.029216

x = 0.0176

[I2] = [Cl2] = 0.0176 M

[ICl] = 0.088 - 2 (0.0176) = 0.0528 M