In a reaction involving Iron Fe and Oxygen It was determined that 4.166g of Iron reacted with 1.803 g of Oxygen. Determine the empirical formula of the compound that resulted

Empirical formula is Fe₂O₃.

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number.

Given dа ta:

Mass of iron = 4.166 g

Mass of oxygen = 1.803 g

Empirical formula = ?

Solution:

Number of gram atoms of Fe = 4.166 / 55.845 = 0.075

Number of gram atoms of O = 1.803 / 15.999 = 0.113

Atomic ratio:

Fe : O

0.075/0.075 : 0.113/0.075

1 : 1.5

Fe : O = 1 : 1.5

Fe : O = 2 (1 : 1.5)

Empirical formula is Fe₂O₃.