Ask Question
20 March, 09:13

At 1000 K, a sample of pure NO2 gas decomposes. 2 NO2 (g) equilibrium reaction arrow 2 NO (g) + O2 (g) The equilibrium constant KP is 158. Analysis shows that the partial pressure of O2 is 0.99 atm at equilibrium. Calculate the pressure of NO and NO2 in the mixture.

+5
Answers (1)
  1. 20 March, 12:11
    0
    0.1575 atm

    Explanation:

    we have that equilibrium constant Kp = (PNO) ₂PO₂ / (PNO₂) ₂

    and it is given to be 158

    ==> Kp = (PNO) ₂PO₂ / (PNO₂) ₂ = 158

    we also have that the partial pressure of O2 (PO₂) = 0.99 atm

    Therefore,

    PO₂ = 0.99 atm = => PNO = 2 (0.99 atm) = 1.98 atm (based on the stoichiometry)

    ==> PNO₂ = √ ((PNO) ₂PO₂ / 158) atm = √ ((1.98) * 2 (0.99) / 158) atm = 0.1575 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “At 1000 K, a sample of pure NO2 gas decomposes. 2 NO2 (g) equilibrium reaction arrow 2 NO (g) + O2 (g) The equilibrium constant KP is 158. ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers