What is the final volume of a 400 ML sample that is subjected To a temperature change from 22 Celsius to 30 Celsius in a pressure change from 760 am MHG to 360 MMHG

The answer to your question is V2 = 867.3 mL

Explanation:

Data

Volume 1 = V1 = 400 ml

Temperature 1 = T1 = 22°C

Pressure 1 = P1 = 760 mmHg

Volume 2 = V2 = ?

Temperature 2 = T2 = 30°C

Pressure 2 = P2 = 360 mmHg

Process

1. - Convert Celsius to Kelvin

T1 = 22 + 273 = 295°K

T2 = 30 + 273 = 303°K

2. - Use the Combined gas law

P1V1/T1 = P2V2/T2

- Solve for V2

V2 = P1V1T2 / T1P2

- Substitution

V2 = (760 x 400 x 303) / (295 x 360)

- Simplification

V2 = 92112000 / 106200

-Result

V2 = 867.3 mL