If 2.00 g of N2 occupies 1.25 L space, how many moles of N2

have a volume of 25.0 L? Assume temperature and pressure

stayed constant.

n₂ = 1.4 mol

Explanation:

Given dа ta:

Mass of nitrogen = 2 g

Initial Volume occupy by nitrogen = 1.25 L

Final volume occupy by nitrogen = 25.0 L

Final number of moles = ?

Solution;

Formula:

V₁ / n₁ = V₂ / n₂

Number of moles of nitrogen:

Number of moles = mass / molar mass

Number of moles = 2 g / 28 g/mol

Number of moles = 0.07 mol

Now we will put the values in formula:

V₁ / n₁ = V₂ / n₂

n₂ = V₂ * n₁ / V₁

n₂ = 25 L * 0.07 mol / 1.25 L

n₂ = 1.75 L. mol / 1.25 L

n₂ = 1.4 mol