A gas has a volume of 4.54 L at 1.65 atm and 75.0°C. At what pressure would the volume

of the gas be increased to 5.33 L if the temperature is increased to 103°C?

The correct answer is 1.52 atm

Explanation:

The formula to be used here is that of the combined gas law

P₁V₁/T₁ = P₂V₂/T₂

where

P₁ is the initial pressure (1.65 atm)

V₁ is the initial volume (4.54 L)

T₁ is the initial temperature (must be converted to kelvin) 75°C + 273 = 348K

P₂ is the final pressure (unknown)

V₂ is the final volume (5.33 L)

T₂ is the final temperature (must be converted to kelvin) 103°C + 273 = 376K

1.65 * 4.54/348 = P₂ * 5.33/376

P₂ = 1.65 * 4.54 * 376 : 5.33 * 348

P₂ = 2816.62 : 1854.84

P₂ = 1.52 atm