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3 August, 05:28

The pOH of an aqueous solution at 25°C was found to be 1.20. The pH of this solution is. The hydronium ion concentration is M. The hydroxide ion concentration is M.

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  1. 3 August, 05:47
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    pH = 12.80

    [H3O+] = 1.58 * 10^-13 M

    [OH-] = 0.063 M

    Explanation:

    Step 1: Data given

    pOH = 1.20

    Temperature = 25.0 °C

    Step 2: Calulate pH

    pH + pOH = 14

    pH = 14 - pOH

    pH = 14 - 1.20 = 12.80

    Step 3: Calculate hydronium ion concentration

    pH = - log[H+] = - log[H3O+]

    12.80 = - log[H3O+]

    10^-12.80 = [H3O+] = 1.58 * 10^-13 M

    Step 4: Calculate the hydroxide ion concentration

    pOH = 1.20 = - log [OH-]

    10^-1.20 = [OH-] = 0.063M

    Step 5: Control [H3O+] and [OH-]

    [H3O+]*[OH-] = 1 * 10^-14

    1.58 * 10^-13 * 0.063 = 1 * 10^-14
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