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29 December, 00:08

A 10.0g sample of H2O (l) at 23.0degrees C absorbs 209 joules of heat. What is the final temp of the H2O (l) sample? Explain.

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  1. 29 December, 00:14
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    Final temperature = 28.0 degrees C.

    Explanation:

    heat absorbed = mass * specific heat * rise in temperature.

    The specific heat of water is 4.186 J / g/C so we have the equation

    209 = 10 * 4.186 * x where x is the temperature increase

    41.86x = 209

    = 5 degrees C.
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