A sample of oxygen occupies a volume of 250mL at 114 kPa. What pressure is required to change the volume to 593 mL?

48.1 kPa

Explanation:

Data Given

initial volume V1 of oxygen gas = 250 mL

initial pressure P1 of oxygen gas = 114 kPa

final volume V2 of oxygen gas = 593 mL

final pressure P2 oxygen gas = ?

Solution:

This problem will be solved by using Boyle's law equation at constant Temperature.

The formula used

P1V1 = P2V2

As we have to find out Volume, so rearrange the above equation

P2 = P1V1 / V2

Put value from the data given

P2 = 114 kPa x 250 mL / 593 mL

P2 = 48.1 kPa

So the final pressure required = 48.1 kPa