Element (X) forms different compounds with Element (Y)

Ex:

Compound 1: XY6 (2.82g)

Compound 2: XY? (1.41g)

Compound 3: XY? (0.94g)

Compound 1: 2.82/6 = 0.47

Compound 2: 1.41/0.47 = 2

Compound 3: 0.94/0.47 = 3

Question

Chemistry

Maggie Taylor

3 November, 10:39

Element (X) forms different compounds with Element (Y)

Ex:

Compound 1: XY6 (2.82g)

Compound 2: XY? (1.41g)

Compound 3: XY? (0.94g)

Compound 1: 2.82/6 = 0.47

Compound 2: 1.41/0.47 = 2

Compound 3: 0.94/0.47 = 3

+4

Answers (1)

Know the Answer?

Rodolfo Dalton · Answer 1

Complete question:

Element (X) forms different compounds with Element (Y)

Ex:

Compound 1: XY6 (2.82g)

Compound 2: XY? (1.41g)

Compound 3: XY? (0.94g)

Compound 1: 2.82/6 = 0.47

Compound 2: 1.41/0.47 = 2

Compound 3: 0.94/0.47 = 3

What Law is this?

Answer:

Law of Multiple Proportions

Explanation:

The Law of Multiple Proportions states that when two elements combine to form more than one compound, they do so in simple whole number ratios of their masses/weights.

Element (X) forms different compounds with Element (Y)Ex:Compound 1: XY6 (2.82g)Compound 2: XY? (1.41g)Compound 3: XY? (0.94g)Compound 1: 2.82/6 = 0.47Compound 2: 1.41/0.47 = 2Compound 3: 0.94/0.47 = 3

Element (X) forms different compounds with Element (Y)

Ex:

Compound 1: XY6 (2.82g)

Compound 2: XY? (1.41g)

Compound 3: XY? (0.94g)

Compound 1: 2.82/6 = 0.47

Compound 2: 1.41/0.47 = 2

Compound 3: 0.94/0.47 = 3