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12 October, 06:15

The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6Li + N2 2Li3N If 12 mol of lithium were reacted with excess nitrogen gas, how many moles of lithium nitride would be produced?

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Answers (2)
  1. 12 October, 07:52
    0
    4.0 moles of lithium nitride will be produced

    Explanation:

    Step 1: Data given

    Number of moles lithium (Li) = 12.0 moles

    Nitrogen gas (N2) is in excess.

    Step 2: The balanced equation

    6Li + N2 → 2Li3N

    Step 3: Calculate moles of lithium nitride (Li3N)

    For 6 moles Lithium we need 1 mol nitrogen gas to produce 2 moles lithium nitride

    For 12.0 moles lithium we'll have 12.0 / 6 = 2.0 moles nitrogen gas to react to produce 12.0 / 3 = 4.0 moles lithium nitride

    4.0 moles of lithium nitride will be produced
  2. 12 October, 08:33
    0
    4 moles of Li₃N will be produced in this reaction

    Explanation:

    The reaction is:

    6Li + N₂ → 2Li₃N

    If the nitrogen gas is the excess reactant, the limiting must be the lithium.

    You always have to make calculations with the limiting reactant. You never use the excess reagent.

    Ratio is 6:2.

    The rule of three to solve this is:

    6 moles of lithium can produce 2 moles of nitride

    Therefore, 12 moles of Li must produce (12. 2) / 6 = 4 moles of nitride
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