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2 August, 11:36

A container of carbon dioxide has a volume of 260 cm at a temperature of 22.0°C. If the

pressure remains constant, what is the volume at 44.0°C?

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  1. 2 August, 14:41
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    V₂ = 279.4 cm³

    Explanation:

    Given dа ta:

    Initial volume = 260 cm³

    Initial temperature = 22.0°C

    Final temperature = 44.0°C

    Final volume = ?

    Solution;

    22.0°C (22 + 273 = 295k)

    44.0°C (44+273 = 317k)

    Formula:

    According to Charles's law

    V₁/T₁ = V₂/T₂

    Now we will put the values in formula:

    V₂ = V₁*T₂ / T₁

    V₂ = 260 cm³ * 317k / 295k

    V₂ = 82420 cm³. k / 295k

    V₂ = 279.4 cm³
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