A sample of an ideal gas at 1.00 atm and a volume of 1.82 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 15.0 atm, what was the volume of the sample? Assume that the temperature was held constant.

Question

Chemistry

Leah Vang

15 February, 05:51

A sample of an ideal gas at 1.00 atm and a volume of 1.82 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 15.0 atm, what was the volume of the sample? Assume that the temperature was held constant.

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Answers (1)

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Cynthia · Answer 1

The answer to your question is Volume = 0.12 L

Explanation:

- Data

Pressure 1 = 1 atm

Volume 1 = 1.82 L

Pressure 2 = 15 atm

Volume 2 = ?

Temperature = constant

- Formula

- To solve this problem use the Boyle's law

P1V1 = P2V2

- Solve for V2

V2 = P1V1 / P2

- Substitution

V2 = (1) (1.82) / 15

- Simplification

V2 = 1.82 / 15

- Result

V2 = 0.12 L