How much heat must be absorbed by 125 of ethanol to change its temperature from 22.3 to 31.0? (Specific heat capacity of ethanol is 2.42)

a. 2.63*103kJ

b. 4.55 kJ

c. 85.2 kJ

d. 2.63 kJ

The heat = 2.63 kJ (option d)

Explanation:

Step 1: Data given

Mass of ethanol = 125 grams

Initial temperature of ethanol = 22.3 °C

Final temperature of ethanol = 31.0 °C

Specific heat of ethanol = 2.42 J/g°C

Step 2: Calculate heat transfer

Q = m*c*ΔT

⇒ with Q = the heat transfer (in joules)

⇒ with m = the mass of ethanol = 125 grams

⇒ with c = the specific heat of ethanol = 2.42 J/g°C

⇒ with ΔT = The change of temeprature = T2 - T1 = 31.0 - 22.3 °C = 8.7 °C

Q = 125 grams * 2.42 J/g°C * 8.7 °C

Q = 2632 J = 2.63 kJ

The heat = 2.63 kJ (option d)