Ask Question
20 May, 00:36

What pressure is required to compress 189.0 liters of air at 1.00 atm into a cylinder whose volume is 28.0 liters

+1
Answers (1)
  1. 20 May, 03:32
    0
    6.75atm

    Explanation:

    The following data were obtained from the question:

    V1 = 189L

    P1 = 1atm

    V2 = 28L

    P2 = ?

    Using Boyle's law equation P1V1 = P2V2 the pressure required to compress the gas can be obtained as follows:

    P1V1 = P2V2

    1 x 189 = P2 x 28

    Divide both side by 28

    P2 = 189/28

    P2 = 6.75atm

    Therefore, the pressure require to compress the gas is 6.75atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What pressure is required to compress 189.0 liters of air at 1.00 atm into a cylinder whose volume is 28.0 liters ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers