If 456 dm3 of krypton at 101kPa and 21C is compressed into a 30.1 dm3 tank at the same temperature what is the pressure of krypton in the tank in kpa

P₂ = 1530.1 KPa

Explanation:

According to Bolye's Law,

The volume of given mass of a gas is inversely proportional to the pressure applied on it at a constant temperature.

V∝1/P

V = kP

V = K/P

PV = k

According to this equation,

P₁V₁ = P₂V₂

Given dа ta:

Initial volume = 456 dm³

Initial pressure = 101 KPa

Final volume = 30.1 dm³

Final pressure = ?

Solution:

Formula:

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 101 KPa * 456 dm³ / 30.1 dm³

P₂ = 46056 / 30.1 dm³

P₂ = 1530.1 KPa