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28 January, 08:26

An aqueous solution that contains 285 ppm of potassium nitrate 1KNO32 is being used to feed plants in a garden. What volume of this solution is needed to prepare 2.0 L of a solution that is 75 ppm in KNO3

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  1. 28 January, 11:41
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    0.53 L

    Explanation:

    Given data

    Initial concentration (C₁) : 285 ppm Initial volume (V₁) : ? Final concentration (C₂) : 75 ppm Final volume (V₂) : 2.0 L

    We can find the required volume of the initial solution using the dilution rule.

    C₁ * V₁ = C₂ * V₂

    V₁ = C₂ * V₂ / C₁

    V₁ = 75 ppm * 2.0 L / 285 ppm

    V₁ = 0.53 L
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