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2 August, 13:25

What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution? (Na=23g; S=32g; O=16 g)

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  1. 2 August, 15:46
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    852g

    Explanation:

    Molarity = 3M

    Volume = 2L

    Molar Mass of Na2SO4 = (23x2) + 32 + (16x4) = 46 + 32 + 64 = 142g/mol

    Number of mole = ?

    Recall:

    Molarity = mole / Volume

    Mole = Molarity x Volume

    Mole = 3 x 2 = 6moles

    Number of mole = Mass / Molar Mass

    Mass = number of mole x molar Mass

    Mass of Na2SO4 = 6 x 142

    Mass of Na2SO4 = 852g
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