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20 August, 22:55

A 251-mL sample of a gas at STP is heated to 45°C. The final pressure is 1.10 atm. Calculate the volume of this gas under the new conditions.

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  1. 21 August, 01:24
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    The volume of the gas under the new conditions is 266 ml

    Explanation:

    We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

    0 ° C = 273K, 45 ° C = 273 + 45 = 318K. The conditions STP are: 1 stm of pressure and 273K of temperature.

    P1xV1/T1 = P2xV2/T2

    1 atmx 251ml/273K=1,10atmx V2/318K

    0,92 atmx L/K = 1,10atmx V2/318K

    V2 = (0,92 atmx L/K x 318K) / 1,10 atm = 265, 79 ml
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