2HgO->2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?

b. I actually collect 2.30 g of O2. What is my percent yield of O2?

Theoretical yield = 3.52 g

Percent yield = 65.34%

Explanation:

Given dа ta:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ = 2.30 g

Solution:

Chemical equation:

2HgO → 2Hg + O₂

Number of moles of HgO = mass / molar mass

Number of moles of HgO = 46.8 g / 216.6 g/mol

Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

HgO : O₂

2 : 1

0.22 : 1/2*0.22 = 0.11 mol

Theoretical yield:

Mass of oxygen = number of moles * molar mass

Mass of oxygen = 0.11 mol * 32 g/mol

Mass of oxygen = 3.52 g

Percent yield:

Percent yield = actual yield / theoretical yield * 100

Percent yield = 2.30 g / 3.52 g * 100

Percent yield = 65.34%