Ask Question
11 March, 09:53

The stopcock connecting a 1.83 L bulb containing helium gas at a pressure of 2.60 atm, and a 6.48 L bulb containing xenon gas at a pressure of 3.56 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, what is the final pressure in the system is atm?

+3
Answers (1)
  1. 11 March, 09:59
    0
    P (final) = 6.16 atm

    Explanation:

    Solution:

    According to the Dalton's law of partial pressure,

    "The total pressure exerted by the mixture of gases is the sum of partial pressure of the individual gases"

    P (total) = P₁ + P₂ + P₃ + ... Pₙ

    Given dа ta:

    Pressure of helium gas = 2.60 atm

    Volume of 1st bulb = 1.83 L

    Pressure of xenon gas = 3.56 atm

    Volume of 2nd bulb = 6.48 L

    Final pressure after mixing of gases=?

    Formula:

    P (final) = P (helium) + P (xenon)

    P (final) = 2.60 atm + 3.56 atm

    P (final) = 6.16 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The stopcock connecting a 1.83 L bulb containing helium gas at a pressure of 2.60 atm, and a 6.48 L bulb containing xenon gas at a pressure ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers