A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammonia. What is the concentration of the original ammonia solution?

M₂ = 0.0745 M

Explanation:

In case of titration, the following formula can be used -

M₁V₁ = M₂V₂

where,

M₁ = concentration of acid,

V₁ = volume of acid,

M₂ = concentration of base,

V₂ = volume of base.

from, the question,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula, the molarity of ammonia, can be calculated as,

M₁V₁ = M₂V₂

0.0952 M * 38.73 mL = M₂ * 49.48 mL

M₂ = 0.0745 M