If 21 mL f gas is subjected to a temperature change from 10.0C to 120C and a pressure change from 1.0 atm to 15 atm, the new volume is:

1.9 mL

1.0 mL

0.53 mL

440 mL

V₂ = 1.41 mL

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given dа ta:

Initial volume = 21 mL

Initial pressure = 1 atm

Initial temperature = 10 °C (10 + 273 = 283 K)

Final temperature = 12 °C (12 + 273 = 285 K)

Final volume = ?

Final pressure = 15 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/T₁ P₂

V₂ = 1 atm * 21 mL * 285 K / 283 K * 15 atm

V₂ = 5985 atm. mL. K / 4245 K. atm

V₂ = 1.41 mL