Ask Question
30 August, 04:49

During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount should have been 105 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O

+3
Answers (1)
  1. 30 August, 07:54
    0
    Actual yield = 86.5g

    Explanation:

    Percent yield = 82.38%

    Theoretical yield = 105g

    Actual yield = x

    Equation of reaction,

    CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

    Percentage yield = (actual yield / theoretical yield) * 100

    82.38% = actual yield / theoretical yield

    82.38 / 100 = x / 105

    Cross multiply and make x the subject of formula

    X = (105 * 82.38) / 100

    X = 86.499g

    X = 86.5g

    Actual yield of CaCl₂ is 86.5g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount should have been ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers