1.95 kJ of heat is required

to raise the temperature of

500 g of lead from 15°C to its final temperature. What is the final temperature if the specific heat capacity of lead is 130 J / (kg°C) ?

45°C

Explanation:

We are given;

Quantity of heat = 1.95 kJ Mass of lead = 500 g Initial temperature = 15° C heat capacity of lead is 130 J/kg°C

We are required to calculate the final temperature;

We need to know that the quantity of heat is given by the formula;

Q = mass, m * specific heat, c * Change in temperature,ΔT

ΔT = final temperature - initial temperature

We can rearrange the formula to calculate the change in temperature

ΔT = Q : (m*c)

Therefore;

ΔT = 1950 J : (0.5 kg * 130 J/Kg°C)

= 30°C

But,

Final temperature = ΔT + Initial temperature

= 15°C + 30°C

= 45°C

Therefore, the final temperature is 45°C