What is the pressure that must be exerted on 300 ML of gas which has been collected at STP so that it may be confined to a volume of 190 ML? Temperature is kept constant.

The answer to your question is P₁ = 0.63 atm

Explanation:

Data

P₁ = x

V₁ = 300 ml

P₂ = 1 atm STP P = 1 atm

V₂ = 190 ml

Process

1. - Use Boyle's law to solve this problem

P₁V₁ = P₂V₂

solve for P₁

P₁ = P₂V₂/V₁

2. - Substitution

P₁ = (1) (190) / (300)

3. - Simplification

P₁ = 190/300

4. - Result

P₁ = 0.63 atm