Calculate the mole fraction of ethyl acetate, in a toluene-ethyl acetate mixture if you mix 1 mL of ethyl acetate and 1 mL of toluene. The density of ethyl acetate (C4H8O2) is 0.898 g/mL; the density of toluene (C7H8) is 0.867 g/mL.

Question

Chemistry

Kamryn Chen

9 October, 09:45

Calculate the mole fraction of ethyl acetate, in a toluene-ethyl acetate mixture if you mix 1 mL of ethyl acetate and 1 mL of toluene. The density of ethyl acetate (C4H8O2) is 0.898 g/mL; the density of toluene (C7H8) is 0.867 g/mL.

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Brody James · Answer 1

Mole fraction ethyl acetate → 0.52

Explanation:

Determine the solution's compound:

Solute: Ethyl-acetate (C₄H₈O₂), molar mass = 88 g/mol

Solvent: Toluene (C₇H₈), molar mass = 92 g/mol

We have density of each, so let's determine their masses:

Density = Mass / volume → Density. volume = Mass

0.898 g/mL. 1mL = 0.898 g of ethyl acetate

0.867 g/mL. 1mL = 0.867 g of tolue

We convert the mass to moles

0.898 g. 1 mol / 88 g = 0.0102 moles of ethyl acetate

0.867 g. 1mol / 92 g = 9.43*10⁻³ moles of tolulene

Mole fraction = Moles of x / Total moles

Mole fraction ethyl acetate = Moles of etyhyl acetate / Total moles

Total moles = 0.0102 + 9.43*10⁻³ = 0.01963

Mole fraction ethyl acetate = 0.0102 / 0.01963 → 0.52