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8 September, 00:45

What is its molar heat of vaporization in kilojoules per mole if its vapor pressure at 20°C is 11.0 torr?

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  1. 8 September, 02:47
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    H. vap = 6.544 kJ/mol

    Explanation:

    Clausius-Clapeyron Equation

    In P = H. vap / RT where T = 20 + 273 = 293K

    H. vap = In P (RT) = In 11 (8.314 x 293) = 6543.861 J/mol = 6.544 kJ/mol
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