You use 4.98 g of Na2SO4, how many grams of barium sulfate are produced?

Na2+Ba (NO3) 2=?

Mass of barium sulfate = 8.17 g

Explanation:

Given dа ta:

Mass of sodium sulfate = 4.98 g

Mass of barium sulfate produced = ?

Solution:

Na₂SO₄ + Ba (NO₃) ₂ → BaSO₄ + 2NaNO₃

Moles of sodium sulfate:

Number of moles = mass/molar mass

Number of moles = 4.98 g / 142.04 g/mol

Number of moles = 0.035 mol

Now we will compare the moles pf sodium sulfate and with barium sulfate.

Na₂SO₄ : BaSO₄

1 : 1

0.035 : 0.035

Mass of barium sulfate:

Mass = number of moles * molar mass

Mass = 0.035 mol * 233.4 g/mol

Mass = 8.17 g