Ammonia (NH3) reacts with oxygen (O2) to produce nitrogen monoxide (NO) and water (H2O). Write and balance the chemical equation. How many liters of NO are produced when 2.0 liters of oxygen reacts with ammonia? Show all work!

There is 1.6 L of NO produced.

Explanation:

I assume you have an excess of NH3 so that O2 is the limiting reagent.

Step 1: Data given

2.0 liters of oxygen reacts with ammonia

Step 2: The balanced equation

4NH3 + 5O2 → 4NO + 6H2O

For 4 moles of NH3, we need 5 moles of O2 to produce 4 moles of NO and 6 moles of H2O

Consider all gases are kept under the same conditions for pressure and temperature, we can express this mole ratio in terms of the volumes occupied by each gas.

This means: when the reaction consumes 4 liters of ammonia (and 5 liters of oxygen) it produces 4 liters of nitrogen monoxide

Now, when there is 2.0 liters of oxygen consumed, there is 4/2.5 = 1.6 L of nitrogen monoxide produced.

There is 1.6 L of NO produced.