What is the number of moles of H2O produced from 221 grams of SnO2?

2.932 moles

Explanation:

Assuming the equation for the reaction in question is;

SnO₂ (s) + 2H₂ (g) → Sn (s) + 2H₂O (l)

Then we can answer the question given;

We are given;

Mass of SnO₂ as 221 grams

We need to calculate the number of moles of H₂O produced;

Step 1: We determine the number of moles of SnO₂ used

To calculate the number of moles we divide mass of of a compound by its molar mass.

Molar mass of SnO₂ = 150.71 g/mol

Therefore;

Number of moles = 221 g : 150.71 g/mol

= 1.466 moles

Step 2: Calculate the number of moles of H₂O produced

From the equation, 1 mole of SnO₂ reacts to produce 2 moles of H₂O

Thus, the mole ratio of SnO₂ : H₂O is 1 : 2

Hence; Moles of H₂O = Moles of SnO₂ * 2

= 1.466 moles * 2

= 2.932 moles

Therefore, 2.932 moles of H₂O are produced.