A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature 303 K, and the final pressure 800 mmHg, what was the initial temperature of helium?

The initial temperature of helium was T1 = 232.23 K

Explanation:

Given dа ta:

Initial volume V1 = 5 L

Initial pressure P1 = 699 mmHg

Final pressure P2 = 800 mmHg

Final volume V2 = 5.7 L

Final temperature T2 = 303 K

Initial temperature T1 = ?

Solution:

Formula:

P1V1/T1 = P2V2/T2

T1 = T2 * P1V1/P2V2

T1 = 303 K * 699 mmHg * 5 L / 800 mmHg * 5.7 L

T1 = 1058985 / 4560

T1 = 232.23 K

initial temperature of helium was 232.23 k.