5.8 L of gas at 760 mm Hg is expanded at constant temperature until the pressure is 430 mm Hg. what is the volume of the gas?

10.3L

Explanation:

The following were obtained from the question:

V1 = 5.8 L

P1 = 760mmHg

P2 = 430mmHg

V2=?

The new volume can be obtain as follows:

P1V1 = P2V2

5.8 x 760 = 430 x V2

Divide both side by 430

V2 = (5.8 x 760) / 430

V2 = 10.3L

Therefore, the new volume is 10.3L