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25 May, 14:35

What is the percent by mass of hydrogen in, C9H6O3

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  1. 25 May, 17:42
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    Hey there!

    Molar mass of (C₉H₆O₃) = 162.14 g/mol

    atomic mass H = 1.007 amu

    Therefore:

    H% = atomic mass H / molar mass (C₉H₆O₃) x 100

    H % = (1.007 / 162.14) x 100 =

    H% = 0.00621 x 100 =

    H% = 0.621
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