5.36 litars of nitrogen gas are at : 25°C and 733 mm Hg

What would be the volume at 129 86 and 1.5 atm

4.6L

Explanation:

Use the equation (P1*V1) / (T1) = (P2*V2) / (T2)

P = pressure

V = volume

T = temperature in kelvins (remember K = C + 273)

Convert atm to mmHg or vise versa

1.5atm * (760mmhg/1atm) = 1140mmHg

(733mmHg * 5.36L) / (298K) = (1140mmHg * V) / (402K)

V = 4.6 or 4.65L (depending on sig figs)