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31 August, 11:59

A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C. Calculate the initial temperature of the piece of copper. Assume that all heat transfer occurs between the copper and the water.

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  1. 31 August, 12:05
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    The answer to your question is: Initial temperature of copper = 67.1°C

    Explanation:

    Data

    mass Copper = 248 g

    volume Water = 390 ml

    T1 water = 22.6°C

    T2 = 39.9°C

    T1 copper = ?

    Specific heat water = 1 cal/g°C

    Specific heat copper = 0.092 cal/g°C

    Formula copper water

    Heat is negative for copper because it releases heat

    - mCp (T2 - T1) = mCp (T2 - T1)

    - (248) (39.9 - T1) = 390 (1) ((39.9 - 22.6) Substitution

    -9895.2 + 248T1 = 390 (17.3) Simplification

    -9895.2 + 248T1 = 6747

    248 T1 = 6747 + 9895.2

    248 T1 = 16642.2

    T1 = 16642.2 / 248

    T1 = 67.1 °C Result
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