How many grams of NaOH are needed to neutralize 20 mL of 0.150 M H2SO4

We need 0.240 grams of NaOH

Explanation:

Step 1: Data given

Volume of a 0.150 M H2SO4 solution = 20 mL = 0.02L

Step 2: The balanced equation:

2NaOH + H2SO4 → Na2SO4 + 2H2O

Step 3: Calculate moles H2SO4

Moles H2SO4 = 0.0200 L * 0.150 M = 0.00300 moles

Step 4: Calculate moles NaOH needed

For 1 mol H2SO4 we need 2 moles of NaOH to neutralize

moles NaOH required = 0.00300 * 2 = 0.00600 moles

Step 5: Calculate mass of NaOH

Mass NaOH = 0.0600 moles * 40 g/mol

mass NaOH = 0.00600 moles * 40 g/mol = 0.240 grams

We need 0.240 grams of NaOH