I need to make 4.5L of a 1.0mol/L solution of acetic acid, HC2H3O2. What volume of concentrated 17.4 Mol/L acid do I need?

0.26 L

Explanation:

Data given

Volume of acetic acid (HC₂H₃O₂) (V1) = ?

Molarity of acetic acid (HC₂H₃O₂) (M1) = 17.4 mol/L

Volume of acetic acid (HC₂H₃O₂) (V2) = 4.5 L

Molarity of acetic acid (HC₂H₃O₂) (M2) = 1.0 mol/L

Solution:

As we diluting the concentrated acetic acid (HC₂H₃O₂)

So, Dilution formula will be used

M1V1 = M2V2

Put values in above equation

17.4 mol/L x V1 = 1.0 mol/L x 4.5 L

Rearrange the above equation

V1 = 1.0 mol/L x 4.5 L / 17.4 mol/L

V1 = 4.5 mol / 17.4 mol/L

V1 = 0.26 L

So 0.26 L of acetic acid (HC₂H₃O₂) is required