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14 October, 23:01

How many molecules of CO2 will be produced by the decomposition

of 24.9 mol of Ca (HCO3) 2 in the following reaction:

Ca (HCO3) 2 = > CaO (s) + 2CO2 (g) + H2O (g).

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  1. 14 October, 23:31
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    2.99*10²⁵ molecules of CO₂ are produced

    Explanation:

    Decomposition reaction is:

    Ca (HCO₃) ₂ = > CaO (s) + 2CO₂ (g) + H₂O (g)

    Ratio is 1:2. Let's make a rule of three:

    1 mol of bicarbonate can produce 2 moles of CO₂

    Therefore, 24.9 moles of bicarbonate may produce, 49.8 moles (24.9.2) / 1

    Let's determine the number of molecules

    1 mol has 6.02*10²³ molecules

    49.8 moles must have (49.8. 6.02*10²³) / 1 = 2.99*10²⁵ molecules
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