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11 December, 19:26

Calculate the mole fraction of each gas in a mixture of 43.6 g Xe and 36.8 g Kr. show work

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  1. 11 December, 22:04
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    Xe = 0.431 mole

    Kr = 0.569 mole

    Explanation:

    We are asked to calculate the mole fraction of each gas

    Let's start from, what is mole fraction?

    Mole fraction is the ratio of the number of moles of a substance to the total number of moles of all substance present in the mixture

    In this question, we are provided with

    Xe - 43.6g

    Let's find the number of mole

    n = m/Mm

    n - number of mole

    m - number of mass in grams

    Mm - number of molar mass

    The molar mass of Xe according to the periodic table is 131.293u

    m - is given to be 43.6g

    n = 43.6g / 131.293g/mol

    n = 0.332mole

    Secondly,

    Kr - 36.8g

    The molar mass of Kr is 83.798

    m = 36.8

    Using the same formula we used above to find mole

    n = 36.8g / 83.798g/mol

    n = 0.439mole

    Let's calculate the total number of mole in the mixture

    Total number of mole = 0.332 + 0.439

    = 0.771 mole

    To find each mole of each gas in the mixture, using this formula

    Mole fraction of a gas = mole of gas A / total mole of the mixture

    In Xe = 0.332 / 0.771

    = 0.431 mole of Xe in the mixture of the gas

    For Kr = 0.439 / 0.771

    = 0.569 mole of Kr in the total mixture
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