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19 April, 05:43

The rate constant for this second‑order reaction is 0.670 M - 1 ⋅ s - 1 at 300 ∘ C. A ⟶ products How long, in seconds, would it take for the concentration of A to decrease from 0.690 M to 0.360 M?

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  1. 19 April, 05:52
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    t = 1.983 s

    Explanation:

    A → Pdts - rA = K (CA) ∧α = - δCA/δt

    ∴ α: order = 2

    ∴ K: rate constant = 0.670/M. s ... T = 300°C

    ⇒ - δCA/δt = (0.670/M. s) (CA²)

    ⇒ - ∫δCA/CA² = (0.670) ∫δt

    ⇒ [ 1/CA - 1/CAo ] = 0.670*t

    ∴ CA = 0.360 M

    ∴ CAo = 0.690 M

    ⇒ [ 1/0.360 - 1/0.690 ] = 0.670*t

    ⇒ [ 1.3285/M ] = (0.670/M. s) * t

    ⇒ t = 1.983 s
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