Use the following half-reactions to design a voltaic cell: Sn4 + (aq) + 2 e - → Sn2 + (aq) Eo = 0.15 V Ag + (aq) + e-→ Ag (s) Eo = 0.80 V What is the overall cell potential? Group of answer choices

E° = 0.65 V

Explanation:

Let's consider the following reductions and their respective standard reduction potentials.

Sn⁴⁺ (aq) + 2 e⁻ → Sn²⁺ (aq) E°red = 0.15 V

Ag⁺ (aq) + e⁻ → Ag (s) E°red = 0.80 V

The reaction with the highest reduction potential will occur as a reduction while the other will occur as an oxidation. The corresponding half-reactions are:

Reduction (cathode) : Ag⁺ (aq) + e⁻ → Ag (s) E°red = 0.80 V

Oxidation (anode) : Sn²⁺ (aq) → Sn⁴⁺ (aq) + 2 e⁻ E°red = 0.15 V

The overall cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = 0.80 V - 0.15 V = 0.65 V