A swimming pool, 10.0 m by 4.0 m is filled to a depth of 3.0 m with water at a temperature of 20.0 degrees Celsius. How much energy is required to raise the temperature of the water to 30.0 degrees Celsius.

5.01*10^9 J is the energy required

Explanation:

This is a calorimetry problem:

Q = m. C. ΔΤ where:

Q = heat

m = mass

ΔΤ = Final T° - Initial T°

First of all we determine the pool's volume with the measures

10 m. 4m. 3m = 120m3

As water density is 1g/mL we can determine water's mass but firstly we must convert the m3 to cm3

1mL = 1cm3

1m3 = 1x10^6 cm3

120 m3. 1x10^6 cm3 / 1m3 = 1.2x10^8 cm3

Water density = water mass / water volume

1 g / mL = water mass / 1.2x10^8 mL

Water mass = 1.2x10^8 g

Then, we replace the data in the formula

Q = 1.2x10^8 g. 4.18 J/g°C (30°C - 20°C)

Q = 1.2x10^8 g. 4.18 J/g°C. 10°C

Q = 5016000000 joules

5.01*10^9 J